4y^2-9y^2=28

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Solution for 4y^2-9y^2=28 equation: 



4y^2-9y^2=28

We move all terms to the left:

4y^2-9y^2-(28)=0

We add all the numbers together, and all the variables

-5y^2-28=0

a = -5; b = 0; c = -28;
Δ = b2-4ac
Δ = 02-4·(-5)·(-28)
Δ = -560
Delta is less than zero, so there is no solution for the equation

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